x^2+1.8x-0.1223=0

Solution for x^2+1.8x-0.1223=0 equation:

x^2+1.8x-0.1223=0

a = 1; b = 1.8; c = -0.1223;
Δ = b2-4ac
Δ = 1.82-4·1·(-0.1223)
Δ = 3.7292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.8)-\sqrt{3.7292}}{2*1}=\frac{-1.8-\sqrt{3.7292}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.8)+\sqrt{3.7292}}{2*1}=\frac{-1.8+\sqrt{3.7292}}{2}
$